x2−9=(x−3)(x+3)x squared minus 9 equals open paren x minus 3 close paren open paren x plus 3 close paren
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yv=(2)2−4(2)+5=4−8+5=1y sub v equals open paren 2 close paren squared minus 4 open paren 2 close paren plus 5 equals 4 minus 8 plus 5 equals 1 ✅ Resources for Full Solutions (GDZ) x2−9=(x−3)(x+3)x squared minus 9 equals open paren x
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2x+6=2(x+3)2 x plus 6 equals 2 open paren x plus 3 close paren For the quadratic Calculate the x-coordinate ( )
x2−92x+6the fraction with numerator x squared minus 9 and denominator 2 x plus 6 end-fraction Use the difference of squares formula
x−32the fraction with numerator x minus 3 and denominator 2 end-fraction . Grade 9: Quadratic Functions Find the coordinates of the vertex of the parabola Identify coefficients. For the quadratic Calculate the x-coordinate ( ). Use the formula x2−9=(x−3)(x+3)x squared minus 9 equals open paren x
xv=−-42⋅1=42=2x sub v equals negative the fraction with numerator negative 4 and denominator 2 center dot 1 end-fraction equals four-halves equals 2 Plug back into the original equation: